Base | Representation |
---|---|
bin | 1011111011111111100011… |
… | …0111001011100100011011 |
3 | 1201110202200202010111012020 |
4 | 2332333320313023210123 |
5 | 3210021103334213110 |
6 | 43525402452545523 |
7 | 2523162114535524 |
oct | 276777067134433 |
9 | 51422622114166 |
10 | 13125300304155 |
11 | 4200454933876 |
12 | 157b9306222a3 |
13 | 742930ca7720 |
14 | 3353a728184b |
15 | 17b644b12d70 |
hex | beff8dcb91b |
13125300304155 has 64 divisors (see below), whose sum is σ = 23346512609280. Its totient is φ = 6252959462400.
The previous prime is 13125300304141. The next prime is 13125300304159. The reversal of 13125300304155 is 55140300352131.
It is not a de Polignac number, because 13125300304155 - 215 = 13125300271387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13125300304159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 197753175 + ... + 197819535.
It is an arithmetic number, because the mean of its divisors is an integer number (364789259520).
Almost surely, 213125300304155 is an apocalyptic number.
13125300304155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13125300304155 is a deficient number, since it is larger than the sum of its proper divisors (10221212305125).
13125300304155 is a wasteful number, since it uses less digits than its factorization.
13125300304155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99132.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 13125300304155 its reverse (55140300352131), we get a palindrome (68265600656286).
The spelling of 13125300304155 in words is "thirteen trillion, one hundred twenty-five billion, three hundred million, three hundred four thousand, one hundred fifty-five".
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