13125340041333 has 64 divisors (see below), whose sum is σ = 19224148070400. Its totient is φ = 7917035592960.

The previous prime is 13125340041323. The next prime is 13125340041347. The reversal of 13125340041333 is 33314004352131.

It is a happy number.

It is not a de Polignac number, because 13125340041333 - 2⁵ = 13125340041301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13125340041294 and 13125340041303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125340041323) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 244798698 + ... + 244852308.

It is an arithmetic number, because the mean of its divisors is an integer number (300377313600).

Almost surely, 2^{13125340041333} is an apocalyptic number.

13125340041333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13125340041333 is a deficient number, since it is larger than the sum of its proper divisors (6098808029067).

13125340041333 is a wasteful number, since it uses less digits than its factorization.

13125340041333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54282.

The product of its (nonzero) digits is 38880, while the sum is 33.

Adding to 13125340041333 its reverse (33314004352131), we get a palindrome (46439344393464).

The spelling of 13125340041333 in words is "thirteen trillion, one hundred twenty-five billion, three hundred forty million, forty-one thousand, three hundred thirty-three".