Base | Representation |
---|---|
bin | 10011000110011001100… |
… | …000000000110101001100 |
3 | 11122110220012012021211110 |
4 | 103012121200000311030 |
5 | 133001040311100330 |
6 | 2442550034252020 |
7 | 163553654510220 |
oct | 23063140006514 |
9 | 4573805167743 |
10 | 1312540331340 |
11 | 466710887797 |
12 | 192467127010 |
13 | 96a06195644 |
14 | 47754c5a780 |
15 | 2421ed28db0 |
hex | 13199800d4c |
1312540331340 has 192 divisors, whose sum is σ = 4266431059968. Its totient is φ = 295287552000.
The previous prime is 1312540331317. The next prime is 1312540331351. The reversal of 1312540331340 is 431330452131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 1312540331298 and 1312540331307.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17885202 + ... + 17958438.
It is an arithmetic number, because the mean of its divisors is an integer number (22220995104).
Almost surely, 21312540331340 is an apocalyptic number.
1312540331340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1312540331340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2133215529984).
1312540331340 is an abundant number, since it is smaller than the sum of its proper divisors (2953890728628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312540331340 is a wasteful number, since it uses less digits than its factorization.
1312540331340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73928 (or 73926 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 1312540331340 its reverse (431330452131), we get a palindrome (1743870783471).
The spelling of 1312540331340 in words is "one trillion, three hundred twelve billion, five hundred forty million, three hundred thirty-one thousand, three hundred forty".
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