Base | Representation |
---|---|
bin | 1011111011111111111101… |
… | …1110110000100010111000 |
3 | 1201110202222111001211012021 |
4 | 2332333333132300202320 |
5 | 3210021320300430040 |
6 | 43525421500524224 |
7 | 2523164633413531 |
oct | 276777736604270 |
9 | 51422874054167 |
10 | 13125411342520 |
11 | 4200501584614 |
12 | 157b961850674 |
13 | 74294acb45b9 |
14 | 3353b7d07688 |
15 | 17b64e74824a |
hex | befff7b08b8 |
13125411342520 has 32 divisors (see below), whose sum is σ = 29532937795920. Its totient is φ = 5250029021440.
The previous prime is 13125411342479. The next prime is 13125411342541. The reversal of 13125411342520 is 2524311452131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2658562 + ... + 5772241.
Almost surely, 213125411342520 is an apocalyptic number.
13125411342520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13125411342520 is an abundant number, since it is smaller than the sum of its proper divisors (16407526453400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13125411342520 is a wasteful number, since it uses less digits than its factorization.
13125411342520 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8469735 (or 8469731 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 13125411342520 its reverse (2524311452131), we get a palindrome (15649722794651).
The spelling of 13125411342520 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, three hundred forty-two thousand, five hundred twenty".
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