Base | Representation |
---|---|
bin | 1011111100000011110100… |
… | …0010100100011110011101 |
3 | 1201110212122110110101121021 |
4 | 2333000331002210132131 |
5 | 3210030424144443240 |
6 | 43530112153204141 |
7 | 2523232344145306 |
oct | 277007502443635 |
9 | 51425573411537 |
10 | 13126444140445 |
11 | 4200991569a19 |
12 | 157bbab700651 |
13 | 742a83c6612c |
14 | 3354751517ad |
15 | 17b6b025754a |
hex | bf03d0a479d |
13126444140445 has 4 divisors (see below), whose sum is σ = 15751732968540. Its totient is φ = 10501155312352.
The previous prime is 13126444140431. The next prime is 13126444140487. The reversal of 13126444140445 is 54404144462131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9898895355001 + 3227548785444 = 3146251^2 + 1796538^2 .
It is a cyclic number.
It is not a de Polignac number, because 13126444140445 - 25 = 13126444140413 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312644414040 + ... + 1312644414049.
It is an arithmetic number, because the mean of its divisors is an integer number (3937933242135).
Almost surely, 213126444140445 is an apocalyptic number.
It is an amenable number.
13126444140445 is a deficient number, since it is larger than the sum of its proper divisors (2625288828095).
13126444140445 is an equidigital number, since it uses as much as digits as its factorization.
13126444140445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2625288828094.
The product of its (nonzero) digits is 737280, while the sum is 43.
The spelling of 13126444140445 in words is "thirteen trillion, one hundred twenty-six billion, four hundred forty-four million, one hundred forty thousand, four hundred forty-five".
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