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13126444140445 = 52625288828089
BaseRepresentation
bin1011111100000011110100…
…0010100100011110011101
31201110212122110110101121021
42333000331002210132131
53210030424144443240
643530112153204141
72523232344145306
oct277007502443635
951425573411537
1013126444140445
114200991569a19
12157bbab700651
13742a83c6612c
143354751517ad
1517b6b025754a
hexbf03d0a479d

13126444140445 has 4 divisors (see below), whose sum is σ = 15751732968540. Its totient is φ = 10501155312352.

The previous prime is 13126444140431. The next prime is 13126444140487. The reversal of 13126444140445 is 54404144462131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9898895355001 + 3227548785444 = 3146251^2 + 1796538^2 .

It is a cyclic number.

It is not a de Polignac number, because 13126444140445 - 25 = 13126444140413 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312644414040 + ... + 1312644414049.

It is an arithmetic number, because the mean of its divisors is an integer number (3937933242135).

Almost surely, 213126444140445 is an apocalyptic number.

It is an amenable number.

13126444140445 is a deficient number, since it is larger than the sum of its proper divisors (2625288828095).

13126444140445 is an equidigital number, since it uses as much as digits as its factorization.

13126444140445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2625288828094.

The product of its (nonzero) digits is 737280, while the sum is 43.

The spelling of 13126444140445 in words is "thirteen trillion, one hundred twenty-six billion, four hundred forty-four million, one hundred forty thousand, four hundred forty-five".

Divisors: 1 5 2625288828089 13126444140445