Base | Representation |
---|---|
bin | 11000011101001101… |
… | …11110100100010111 |
3 | 1020220001102010211212 |
4 | 30032212332210113 |
5 | 203342240010123 |
6 | 10010513252035 |
7 | 643242110213 |
oct | 141646764427 |
9 | 36801363755 |
10 | 13130000663 |
11 | 56285a791a |
12 | 266526401b |
13 | 13132ba880 |
14 | 8c7b29943 |
15 | 51ca80878 |
hex | 30e9be917 |
13130000663 has 4 divisors (see below), whose sum is σ = 14140000728. Its totient is φ = 12120000600.
The previous prime is 13130000651. The next prime is 13130000683. The reversal of 13130000663 is 36600003131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13130000663 - 220 = 13128952087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130000603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505000013 + ... + 505000038.
It is an arithmetic number, because the mean of its divisors is an integer number (3535000182).
Almost surely, 213130000663 is an apocalyptic number.
13130000663 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13130000663 is a deficient number, since it is larger than the sum of its proper divisors (1010000065).
13130000663 is a wasteful number, since it uses less digits than its factorization.
13130000663 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1010000064.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 13130000663 its reverse (36600003131), we get a palindrome (49730003794).
The spelling of 13130000663 in words is "thirteen billion, one hundred thirty million, six hundred sixty-three", and thus it is an aban number.
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