Base | Representation |
---|---|
bin | 11101110110101010111110… |
… | …001111101110111001111000 |
3 | 122012220012010120221212111101 |
4 | 131312222332033232321320 |
5 | 114202211100030042130 |
6 | 1143130313332341144 |
7 | 36441064606502014 |
oct | 3566527617567170 |
9 | 565805116855441 |
10 | 131300342034040 |
11 | 389221870a3683 |
12 | 12886a76a747b4 |
13 | 58357524a6a1a |
14 | 245cd82d3d544 |
15 | 102a6535321ca |
hex | 776abe3eee78 |
131300342034040 has 32 divisors (see below), whose sum is σ = 295490741564880. Its totient is φ = 52508586237952.
The previous prime is 131300342034011. The next prime is 131300342034047. The reversal of 131300342034040 is 40430243003131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131300342034047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 360771337 + ... + 361135096.
Almost surely, 2131300342034040 is an apocalyptic number.
131300342034040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131300342034040 is an abundant number, since it is smaller than the sum of its proper divisors (164190399530840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131300342034040 is a wasteful number, since it uses less digits than its factorization.
131300342034040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 721910991 (or 721910987 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 131300342034040 its reverse (40430243003131), we get a palindrome (171730585037171).
The spelling of 131300342034040 in words is "one hundred thirty-one trillion, three hundred billion, three hundred forty-two million, thirty-four thousand, forty".
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