1313005235 has 4 divisors (see below), whose sum is σ = 1575606288. Its totient is φ = 1050404184.

The previous prime is 1313005153. The next prime is 1313005283. The reversal of 1313005235 is 5325003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313005235 - 2¹² = 1313001139 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1313005235.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131300519 + ... + 131300528.

It is an arithmetic number, because the mean of its divisors is an integer number (393901572).

Almost surely, 2^1313005235 is an apocalyptic number.

1313005235 is a deficient number, since it is larger than the sum of its proper divisors (262601053).

1313005235 is an equidigital number, since it uses as much as digits as its factorization.

1313005235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262601052.

The product of its (nonzero) digits is 1350, while the sum is 23.

The square root of 1313005235 is about 36235.4141000210. The cubic root of 1313005235 is about 1095.0202549717.

Adding to 1313005235 its reverse (5325003131), we get a palindrome (6638008366).

The spelling of 1313005235 in words is "one billion, three hundred thirteen million, five thousand, two hundred thirty-five".