| Base | Representation |
|---|---|
| bin | 111101001001000101… |
| … | …0000001100000000000 |
| 3 | 110112220121012222201110 |
| 4 | 1322102022001200000 |
| 5 | 4122401041320000 |
| 6 | 140152514403320 |
| 7 | 12325523051061 |
| oct | 1722212014000 |
| 9 | 415817188643 |
| 10 | 131301120000 |
| 11 | 50759071916 |
| 12 | 21544590540 |
| 13 | c4c661251b |
| 14 | 64d81dc568 |
| 15 | 36371c5850 |
| hex | 1e92281800 |
131301120000 has 480 divisors, whose sum is σ = 451943331840. Its totient is φ = 33853440000.
The previous prime is 131301119953. The next prime is 131301120001. The reversal of 131301120000 is 21103131.
It is a tau number, because it is divible by the number of its divisors (480).
It is a super-2 number, since 2×1313011200002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131301120001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 119039449 + ... + 119040551.
It is an arithmetic number, because the mean of its divisors is an integer number (941548608).
Almost surely, 2131301120000 is an apocalyptic number.
131301120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131301120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (225971665920).
131301120000 is an abundant number, since it is smaller than the sum of its proper divisors (320642211840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131301120000 is an equidigital number, since it uses as much as digits as its factorization.
131301120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1179 (or 1144 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 131301120000 its reverse (21103131), we get a palindrome (131322223131).
The spelling of 131301120000 in words is "one hundred thirty-one billion, three hundred one million, one hundred twenty thousand".
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