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131301133000102 = 2135050043576927
BaseRepresentation
bin11101110110101011101101…
…011001000001110110100110
3122012220021011201022002221201
4131312223231121001312212
5114202214210022000402
61143130524025433114
736441123322551352
oct3566535531016646
9565807151262851
10131301133000102
113892255262413a
121288705793b79a
13583584a315990
14245d019dd6462
15102a69cbc2687
hex776aed641da6

131301133000102 has 8 divisors (see below), whose sum is σ = 212101830230976. Its totient is φ = 60600522923112.

The previous prime is 131301133000073. The next prime is 131301133000151. The reversal of 131301133000102 is 201000331103131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1313011330001022 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131301133000102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2525021788438 + ... + 2525021788489.

It is an arithmetic number, because the mean of its divisors is an integer number (26512728778872).

Almost surely, 2131301133000102 is an apocalyptic number.

131301133000102 is a deficient number, since it is larger than the sum of its proper divisors (80800697230874).

131301133000102 is a wasteful number, since it uses less digits than its factorization.

131301133000102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5050043576942.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131301133000102 its reverse (201000331103131), we get a palindrome (332301464103233).

The spelling of 131301133000102 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred thirty-three million, one hundred two", and thus it is an aban number.

Divisors: 1 2 13 26 5050043576927 10100087153854 65650566500051 131301133000102