131302104212020 has 96 divisors (see below), whose sum is σ = 317238777386496. Its totient is φ = 44715953664000.

The previous prime is 131302104212009. The next prime is 131302104212033. The reversal of 131302104212020 is 20212401203131.

It is a super-2 number, since 2×131302104212020² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131302104211982 and 131302104212000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 255812440 + ... + 256325200.

It is an arithmetic number, because the mean of its divisors is an integer number (3304570597776).

Almost surely, 2^{131302104212020} is an apocalyptic number.

131302104212020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131302104212020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158619388693248).

131302104212020 is an abundant number, since it is smaller than the sum of its proper divisors (185936673174476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131302104212020 is a wasteful number, since it uses less digits than its factorization.

131302104212020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 525041 (or 525039 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 131302104212020 its reverse (20212401203131), we get a palindrome (151514505415151).

The spelling of 131302104212020 in words is "one hundred thirty-one trillion, three hundred two billion, one hundred four million, two hundred twelve thousand, twenty".