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1313021111333 = 4543928896347
BaseRepresentation
bin10011000110110110001…
…010000010110000100101
311122112010200212102222212
4103012312022002300211
5133003031401030313
62443105451133205
7163601613204161
oct23066612026045
94575120772885
101313021111333
11466938206928
12192580144205
1396a8197b349
144779ca4bca1
152424c1473a8
hex131b6282c25

1313021111333 has 4 divisors (see below), whose sum is σ = 1313050053120. Its totient is φ = 1312992169548.

The previous prime is 1313021111327. The next prime is 1313021111357. The reversal of 1313021111333 is 3331111203131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313021111333 is a prime.

It is a super-2 number, since 2×13130211113332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1313021111299 and 1313021111308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313021113333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14402735 + ... + 14493612.

It is an arithmetic number, because the mean of its divisors is an integer number (328262513280).

Almost surely, 21313021111333 is an apocalyptic number.

It is an amenable number.

1313021111333 is a deficient number, since it is larger than the sum of its proper divisors (28941787).

1313021111333 is an equidigital number, since it uses as much as digits as its factorization.

1313021111333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28941786.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1313021111333 its reverse (3331111203131), we get a palindrome (4644132314464).

The spelling of 1313021111333 in words is "one trillion, three hundred thirteen billion, twenty-one million, one hundred eleven thousand, three hundred thirty-three".

Divisors: 1 45439 28896347 1313021111333