Base | Representation |
---|---|
bin | 11101110110101110011010… |
… | …110111010101000011100000 |
3 | 122012220112200112201211000212 |
4 | 131312232122313111003200 |
5 | 114202241140102321230 |
6 | 1143132124513433252 |
7 | 36441255412552430 |
oct | 3566563267250340 |
9 | 565815615654025 |
10 | 131304043401440 |
11 | 389238064577a8 |
12 | 1288772a56b828 |
13 | 5835bc2288b50 |
14 | 245d2147582c0 |
15 | 102a7bd468895 |
hex | 776b9add50e0 |
131304043401440 has 192 divisors, whose sum is σ = 381874077244800. Its totient is φ = 41546605363200.
The previous prime is 131304043401439. The next prime is 131304043401469. The reversal of 131304043401440 is 44104340403131.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a junction number, because it is equal to n+sod(n) for n = 131304043401397 and 131304043401406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66719540 + ... + 68659340.
It is an arithmetic number, because the mean of its divisors is an integer number (1988927485650).
Almost surely, 2131304043401440 is an apocalyptic number.
131304043401440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131304043401440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190937038622400).
131304043401440 is an abundant number, since it is smaller than the sum of its proper divisors (250570033843360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131304043401440 is a wasteful number, since it uses less digits than its factorization.
131304043401440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1944485 (or 1944477 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 131304043401440 its reverse (44104340403131), we get a palindrome (175408383804571).
The spelling of 131304043401440 in words is "one hundred thirty-one trillion, three hundred four billion, forty-three million, four hundred one thousand, four hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •