13131103101101 has 4 divisors (see below), whose sum is σ = 13131141258912. Its totient is φ = 13131064943292.

The previous prime is 13131103100993. The next prime is 13131103101191. The reversal of 13131103101101 is 10110130113131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13131103101101 - 2¹⁰ = 13131103100077 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13131103101101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131103101191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18557975 + ... + 19252548.

It is an arithmetic number, because the mean of its divisors is an integer number (3282785314728).

Almost surely, 2^{13131103101101} is an apocalyptic number.

It is an amenable number.

13131103101101 is a deficient number, since it is larger than the sum of its proper divisors (38157811).

13131103101101 is an equidigital number, since it uses as much as digits as its factorization.

13131103101101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38157810.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 13131103101101 its reverse (10110130113131), we get a palindrome (23241233214232).

The spelling of 13131103101101 in words is "thirteen trillion, one hundred thirty-one billion, one hundred three million, one hundred one thousand, one hundred one".