13131111030301 has 4 divisors (see below), whose sum is σ = 14324848396704. Its totient is φ = 11937373663900.

The previous prime is 13131111030269. The next prime is 13131111030341. The reversal of 13131111030301 is 10303011113131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13131111030301 - 2⁵ = 13131111030269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131111030341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596868683185 + ... + 596868683206.

It is an arithmetic number, because the mean of its divisors is an integer number (3581212099176).

Almost surely, 2^{13131111030301} is an apocalyptic number.

13131111030301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13131111030301 is a deficient number, since it is larger than the sum of its proper divisors (1193737366403).

13131111030301 is a wasteful number, since it uses less digits than its factorization.

13131111030301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1193737366402.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 13131111030301 its reverse (10303011113131), we get a palindrome (23434122143432).

The spelling of 13131111030301 in words is "thirteen trillion, one hundred thirty-one billion, one hundred eleven million, thirty thousand, three hundred one".