13131111030341 has 2 divisors, whose sum is σ = 13131111030342. Its totient is φ = 13131111030340.

The previous prime is 13131111030269. The next prime is 13131111030371. The reversal of 13131111030341 is 14303011113131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7098339961441 + 6032771068900 = 2664271^2 + 2456170^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131111030341 - 2¹⁰ = 13131111029317 is a prime.

It is a super-3 number, since 3×13131111030341³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131111030371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565555515170 + 6565555515171.

It is an arithmetic number, because the mean of its divisors is an integer number (6565555515171).

Almost surely, 2^{13131111030341} is an apocalyptic number.

It is an amenable number.

13131111030341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131111030341 is an equidigital number, since it uses as much as digits as its factorization.

13131111030341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 13131111030341 its reverse (14303011113131), we get a palindrome (27434122143472).

The spelling of 13131111030341 in words is "thirteen trillion, one hundred thirty-one billion, one hundred eleven million, thirty thousand, three hundred forty-one".