13131321202031 has 4 divisors (see below), whose sum is σ = 13903751860992. Its totient is φ = 12358890543072.

The previous prime is 13131321202001. The next prime is 13131321202037. The reversal of 13131321202031 is 13020212313131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131321202031 is a prime.

It is a super-2 number, since 2×13131321202031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13131321201988 and 13131321202006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131321202037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386215329455 + ... + 386215329488.

It is an arithmetic number, because the mean of its divisors is an integer number (3475937965248).

Almost surely, 2^{13131321202031} is an apocalyptic number.

13131321202031 is a deficient number, since it is larger than the sum of its proper divisors (772430658961).

13131321202031 is an equidigital number, since it uses as much as digits as its factorization.

13131321202031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 772430658960.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13131321202031 its reverse (13020212313131), we get a palindrome (26151533515162).

Subtracting from 13131321202031 its reverse (13020212313131), we obtain a square (111108888900 = 333330²).

The spelling of 13131321202031 in words is "thirteen trillion, one hundred thirty-one billion, three hundred twenty-one million, two hundred two thousand, thirty-one".