Base | Representation |
---|---|
bin | 11101110110110111000100… |
… | …100000101001001000010100 |
3 | 122012221102122212221010202200 |
4 | 131312313010200221020110 |
5 | 114202414201000011040 |
6 | 1143140302325204500 |
7 | 36442034531611155 |
oct | 3566670440511024 |
9 | 565842585833680 |
10 | 131313332032020 |
11 | 389277426673a6 |
12 | 128894a1260730 |
13 | 5836a42785c68 |
14 | 245d85622392c |
15 | 102ab63b5a630 |
hex | 776dc4829214 |
131313332032020 has 288 divisors, whose sum is σ = 423526290969600. Its totient is φ = 32858652423168.
The previous prime is 131313332031983. The next prime is 131313332032067. The reversal of 131313332032020 is 20230233313131.
131313332032020 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 1 + 3 + 332 + 0 + 320 + 2 + 0 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2229058326 + ... + 2229117234.
It is an arithmetic number, because the mean of its divisors is an integer number (1470577399200).
Almost surely, 2131313332032020 is an apocalyptic number.
131313332032020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131313332032020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (211763145484800).
131313332032020 is an abundant number, since it is smaller than the sum of its proper divisors (292212958937580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131313332032020 is a wasteful number, since it uses less digits than its factorization.
131313332032020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69159 (or 69154 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 27.
Adding to 131313332032020 its reverse (20230233313131), we get a palindrome (151543565345151).
The spelling of 131313332032020 in words is "one hundred thirty-one trillion, three hundred thirteen billion, three hundred thirty-two million, thirty-two thousand, twenty".
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