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13131344442000 = 243531727572863
BaseRepresentation
bin1011111100010110000100…
…0111101111001010010000
31201111100021222020111121110
42333011201013233022100
53210120443134121000
643532242323453320
72523464646054621
oct277054107571220
951440258214543
1013131344442000
114202a76671014
121580b38827240
13743385258555
143357bbc9da48
1517b89a568850
hexbf1611ef290

13131344442000 has 240 divisors, whose sum is σ = 44972270733312. Its totient is φ = 3295709542400.

The previous prime is 13131344441959. The next prime is 13131344442067. The reversal of 13131344442000 is 24444313131.

13131344442000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2052432 + ... + 5520431.

Almost surely, 213131344442000 is an apocalyptic number.

13131344442000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13131344442000 is an abundant number, since it is smaller than the sum of its proper divisors (31840926291312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131344442000 is a wasteful number, since it uses less digits than its factorization.

13131344442000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7572923 (or 7572890 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 13131344442000 its reverse (24444313131), we get a palindrome (13155788755131).

The spelling of 13131344442000 in words is "thirteen trillion, one hundred thirty-one billion, three hundred forty-four million, four hundred forty-two thousand".