13131433125340 has 48 divisors (see below), whose sum is σ = 27827341668000. Its totient is φ = 5204868745472.

The previous prime is 13131433125331. The next prime is 13131433125493. The reversal of 13131433125340 is 4352133413131.

It is a junction number, because it is equal to n+sod(n) for n = 13131433125296 and 13131433125305.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4009759 + ... + 6506998.

It is an arithmetic number, because the mean of its divisors is an integer number (579736284750).

Almost surely, 2^{13131433125340} is an apocalyptic number.

13131433125340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13131433125340 is an abundant number, since it is smaller than the sum of its proper divisors (14695908542660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131433125340 is a wasteful number, since it uses less digits than its factorization.

13131433125340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10517334 (or 10517332 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 13131433125340 its reverse (4352133413131), we get a palindrome (17483566538471).

The spelling of 13131433125340 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-three million, one hundred twenty-five thousand, three hundred forty".