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131320220111 = 157836434523
BaseRepresentation
bin111101001001101001…
…0111000100111001111
3110112221221011101010222
41322103102320213033
54122420434020421
6140154440021555
712326144311403
oct1722322704717
9415857141128
10131320220111
1150768928033
122154aa618bb
13c4ca56c172
1464da971103
153638be9cab
hex1e934b89cf

131320220111 has 4 divisors (see below), whose sum is σ = 132156654792. Its totient is φ = 130483785432.

The previous prime is 131320220107. The next prime is 131320220113. The reversal of 131320220111 is 111022023131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131320220111 - 22 = 131320220107 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131320220111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131320220113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418217105 + ... + 418217418.

It is an arithmetic number, because the mean of its divisors is an integer number (33039163698).

Almost surely, 2131320220111 is an apocalyptic number.

131320220111 is a deficient number, since it is larger than the sum of its proper divisors (836434681).

131320220111 is an equidigital number, since it uses as much as digits as its factorization.

131320220111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 836434680.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131320220111 its reverse (111022023131), we get a palindrome (242342243242).

The spelling of 131320220111 in words is "one hundred thirty-one billion, three hundred twenty million, two hundred twenty thousand, one hundred eleven".

Divisors: 1 157 836434523 131320220111