Base | Representation |
---|---|
bin | 1011111100011000111001… |
… | …0010011001101011010111 |
3 | 1201111102020210010020001112 |
4 | 2333012032102121223113 |
5 | 3210124021131243221 |
6 | 43532445433245235 |
7 | 2523522510025535 |
oct | 277061622315327 |
9 | 51442223106045 |
10 | 13132102212311 |
11 | 4203325389075 |
12 | 158110a56381b |
13 | 743476243a54 |
14 | 335850795155 |
15 | 17b8e1d4d15b |
hex | bf18e499ad7 |
13132102212311 has 4 divisors (see below), whose sum is σ = 13132302636432. Its totient is φ = 13131901788192.
The previous prime is 13132102212241. The next prime is 13132102212323. The reversal of 13132102212311 is 11321220123131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13132102212311 - 210 = 13132102211287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132102212811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100113746 + ... + 100244831.
It is an arithmetic number, because the mean of its divisors is an integer number (3283075659108).
Almost surely, 213132102212311 is an apocalyptic number.
13132102212311 is a deficient number, since it is larger than the sum of its proper divisors (200424121).
13132102212311 is an equidigital number, since it uses as much as digits as its factorization.
13132102212311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 200424120.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13132102212311 its reverse (11321220123131), we get a palindrome (24453322335442).
The spelling of 13132102212311 in words is "thirteen trillion, one hundred thirty-two billion, one hundred two million, two hundred twelve thousand, three hundred eleven".
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