Base | Representation |
---|---|
bin | 111101001001110010… |
… | …1001111111000110011 |
3 | 110112222021012221121110 |
4 | 1322103211033320303 |
5 | 4122423202042120 |
6 | 140155131124403 |
7 | 12326233241226 |
oct | 1722345177063 |
9 | 415867187543 |
10 | 131325034035 |
11 | 50770615888 |
12 | 215505a3703 |
13 | c4cb566340 |
14 | 64db4655bd |
15 | 363934b2e0 |
hex | 1e9394fe33 |
131325034035 has 16 divisors (see below), whose sum is σ = 226283135904. Its totient is φ = 64652324352.
The previous prime is 131325034007. The next prime is 131325034073. The reversal of 131325034035 is 530430523131.
It is not a de Polignac number, because 131325034035 - 25 = 131325034003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131325033993 and 131325034011.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 336730662 + ... + 336731051.
It is an arithmetic number, because the mean of its divisors is an integer number (14142695994).
Almost surely, 2131325034035 is an apocalyptic number.
131325034035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131325034035 is a deficient number, since it is larger than the sum of its proper divisors (94958101869).
131325034035 is a wasteful number, since it uses less digits than its factorization.
131325034035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 673461734.
The product of its (nonzero) digits is 16200, while the sum is 30.
Adding to 131325034035 its reverse (530430523131), we get a palindrome (661755557166).
The spelling of 131325034035 in words is "one hundred thirty-one billion, three hundred twenty-five million, thirty-four thousand, thirty-five".
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