131330231420130 has 40 divisors (see below), whose sum is σ = 353132400042972. Its totient is φ = 35021395045152.

The previous prime is 131330231420119. The next prime is 131330231420131. The reversal of 131330231420130 is 31024132033131.

131330231420130 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 3 + 0 + 231 + 420 + 1 + 3 + 0 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 130995098105481 + 335133314649 = 11445309^2 + 578907^2 .

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 131330231420094 and 131330231420103.

It is not an unprimeable number, because it can be changed into a prime (131330231420131) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 81068043277 + ... + 81068044896.

Almost surely, 2^{131330231420130} is an apocalyptic number.

131330231420130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131330231420130 is an abundant number, since it is smaller than the sum of its proper divisors (221802168622842).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131330231420130 is a wasteful number, since it uses less digits than its factorization.

131330231420130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162136088192 (or 162136088183 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 131330231420130 its reverse (31024132033131), we get a palindrome (162354363453261).

The spelling of 131330231420130 in words is "one hundred thirty-one trillion, three hundred thirty billion, two hundred thirty-one million, four hundred twenty thousand, one hundred thirty".