Base | Representation |
---|---|
bin | 10011000111000110111… |
… | …101010111110011000011 |
3 | 11122112212100021222201022 |
4 | 103013012331113303003 |
5 | 133004121032033212 |
6 | 2443153441100055 |
7 | 163611605221562 |
oct | 23070675276303 |
9 | 4575770258638 |
10 | 1313303002307 |
11 | 466a7234177a |
12 | 19263a62762b |
13 | 96ac81a863a |
14 | 477c8269bd9 |
15 | 24266c7a772 |
hex | 131c6f57cc3 |
1313303002307 has 4 divisors (see below), whose sum is σ = 1316679102960. Its totient is φ = 1309926901656.
The previous prime is 1313303002283. The next prime is 1313303002357. The reversal of 1313303002307 is 7032003033131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1313303002307 - 232 = 1309008035011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313303002357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1688049743 + ... + 1688050520.
It is an arithmetic number, because the mean of its divisors is an integer number (329169775740).
Almost surely, 21313303002307 is an apocalyptic number.
1313303002307 is a deficient number, since it is larger than the sum of its proper divisors (3376100653).
1313303002307 is an equidigital number, since it uses as much as digits as its factorization.
1313303002307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3376100652.
The product of its (nonzero) digits is 3402, while the sum is 26.
Adding to 1313303002307 its reverse (7032003033131), we get a palindrome (8345306035438).
The spelling of 1313303002307 in words is "one trillion, three hundred thirteen billion, three hundred three million, two thousand, three hundred seven".
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