| Base | Representation |
|---|---|
| bin | 11101110111000111101000… |
| … | …010101101100001101010000 |
| 3 | 122020000010120001222102001200 |
| 4 | 131313013220111230031100 |
| 5 | 114203212104412310000 |
| 6 | 1143152402545231200 |
| 7 | 36443234260462131 |
| oct | 3567075025541520 |
| 9 | 566003501872050 |
| 10 | 131331113010000 |
| 11 | 38934237554322 |
| 12 | 12890a24032500 |
| 13 | 58386174cbcc7 |
| 14 | 2460661919c88 |
| 15 | 102b354b9d500 |
| hex | 7771e856c350 |
131331113010000 has 600 divisors, whose sum is σ = 461800135203264. Its totient is φ = 34830297600000.
The previous prime is 131331113009963. The next prime is 131331113010037. The reversal of 131331113010000 is 10311133131.
131331113010000 is a `hidden beast` number, since 1 + 31 + 331 + 1 + 1 + 301 + 0 + 0 + 0 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (131331113009963) and next prime (131331113010037).
It is a tau number, because it is divible by the number of its divisors (600).
It is a super-2 number, since 2×1313311130100002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 12523224757 + ... + 12523235243.
Almost surely, 2131331113010000 is an apocalyptic number.
131331113010000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131331113010000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (230900067601632).
131331113010000 is an abundant number, since it is smaller than the sum of its proper divisors (330469022193264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131331113010000 is a wasteful number, since it uses less digits than its factorization.
131331113010000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11269 (or 11245 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 131331113010000 its reverse (10311133131), we get a palindrome (131341424143131).
The spelling of 131331113010000 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, one hundred thirteen million, ten thousand".
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