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13133121023 = 111193920093
BaseRepresentation
bin11000011101100101…
…11000010111111111
31020220021021200011202
430032302320113333
5203344034333043
610011104210115
7643310454401
oct141662702777
936807250152
1013133121023
11562a339230
12266630993b
131313b40c39
148c82dcb71
1551ce9a1b8
hex30ecb85ff

13133121023 has 4 divisors (see below), whose sum is σ = 14327041128. Its totient is φ = 11939200920.

The previous prime is 13133121019. The next prime is 13133121031. The reversal of 13133121023 is 32012133131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13133121023 - 22 = 13133121019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13133120986 and 13133121004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13133121013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596960036 + ... + 596960057.

It is an arithmetic number, because the mean of its divisors is an integer number (3581760282).

Almost surely, 213133121023 is an apocalyptic number.

13133121023 is a deficient number, since it is larger than the sum of its proper divisors (1193920105).

13133121023 is a wasteful number, since it uses less digits than its factorization.

13133121023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1193920104.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13133121023 its reverse (32012133131), we get a palindrome (45145254154).

The spelling of 13133121023 in words is "thirteen billion, one hundred thirty-three million, one hundred twenty-one thousand, twenty-three".

Divisors: 1 11 1193920093 13133121023