131333111320 has 32 divisors (see below), whose sum is σ = 295883834400. Its totient is φ = 52464918528.

The previous prime is 131333111293. The next prime is 131333111321. The reversal of 131333111320 is 23111333131.

It is a super-2 number, since 2×131333111320² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131333111291 and 131333111300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131333111321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2104044 + ... + 2165563.

It is an arithmetic number, because the mean of its divisors is an integer number (9246369825).

Almost surely, 2^131333111320 is an apocalyptic number.

131333111320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131333111320 is an abundant number, since it is smaller than the sum of its proper divisors (164550723080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131333111320 is a wasteful number, since it uses less digits than its factorization.

131333111320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4270387 (or 4270383 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 131333111320 its reverse (23111333131), we get a palindrome (154444444451).

The spelling of 131333111320 in words is "one hundred thirty-one billion, three hundred thirty-three million, one hundred eleven thousand, three hundred twenty".