Base | Representation |
---|---|
bin | 11101110111001001100001… |
… | …001110011001101100101111 |
3 | 122020000022210102021012120111 |
4 | 131313021201032121230233 |
5 | 114203230233113023234 |
6 | 1143153340115200451 |
7 | 36443335445353264 |
oct | 3567114116315457 |
9 | 566008712235514 |
10 | 131333141142319 |
11 | 38935088366136 |
12 | 128912ab2a6127 |
13 | 583887b7461bc |
14 | 24607b501926b |
15 | 102b422c6b664 |
hex | 777261399b2f |
131333141142319 has 4 divisors (see below), whose sum is σ = 134387400238696. Its totient is φ = 128278882045944.
The previous prime is 131333141142283. The next prime is 131333141142331. The reversal of 131333141142319 is 913241141333131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131333141142319 - 215 = 131333141109551 is a prime.
It is a super-2 number, since 2×1313331411423192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131333141142389) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1527129548124 + ... + 1527129548209.
It is an arithmetic number, because the mean of its divisors is an integer number (33596850059674).
Almost surely, 2131333141142319 is an apocalyptic number.
131333141142319 is a deficient number, since it is larger than the sum of its proper divisors (3054259096377).
131333141142319 is an equidigital number, since it uses as much as digits as its factorization.
131333141142319 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3054259096376.
The product of its digits is 69984, while the sum is 40.
The spelling of 131333141142319 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred forty-one million, one hundred forty-two thousand, three hundred nineteen".
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