1313402050021 has 4 divisors (see below), whose sum is σ = 1321767668332. Its totient is φ = 1305036431712.

The previous prime is 1313402050007. The next prime is 1313402050069. The reversal of 1313402050021 is 1200502043131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 742794041025 + 570608008996 = 861855^2 + 755386^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313402050021 - 2²⁵ = 1313368495589 is a prime.

It is a super-2 number, since 2×1313402050021² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313402049974 and 1313402050001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313402050001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4182808920 + ... + 4182809233.

It is an arithmetic number, because the mean of its divisors is an integer number (330441917083).

Almost surely, 2^{1313402050021} is an apocalyptic number.

It is an amenable number.

1313402050021 is a deficient number, since it is larger than the sum of its proper divisors (8365618311).

1313402050021 is an equidigital number, since it uses as much as digits as its factorization.

1313402050021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8365618310.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 1313402050021 its reverse (1200502043131), we get a palindrome (2513904093152).

The spelling of 1313402050021 in words is "one trillion, three hundred thirteen billion, four hundred two million, fifty thousand, twenty-one".