Base | Representation |
---|---|
bin | 11000011101101101… |
… | …01100100100001110 |
3 | 1020220100011111012110 |
4 | 30032312230210032 |
5 | 203344313334410 |
6 | 10011141444450 |
7 | 643322121426 |
oct | 141666544416 |
9 | 36810144173 |
10 | 13134121230 |
11 | 562a96174a |
12 | 2666710726 |
13 | 1314101289 |
14 | 8c84bd486 |
15 | 51d0e6720 |
hex | 30edac90e |
13134121230 has 64 divisors (see below), whose sum is σ = 32584808448. Its totient is φ = 3384650880.
The previous prime is 13134121229. The next prime is 13134121249. The reversal of 13134121230 is 3212143131.
13134121230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13134121197 and 13134121206.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 672057 + ... + 691323.
It is an arithmetic number, because the mean of its divisors is an integer number (509137632).
Almost surely, 213134121230 is an apocalyptic number.
13134121230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13134121230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16292404224).
13134121230 is an abundant number, since it is smaller than the sum of its proper divisors (19450687218).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134121230 is a wasteful number, since it uses less digits than its factorization.
13134121230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20041.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13134121230 its reverse (3212143131), we get a palindrome (16346264361).
The spelling of 13134121230 in words is "thirteen billion, one hundred thirty-four million, one hundred twenty-one thousand, two hundred thirty".
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