1313413342544 has 10 divisors (see below), whose sum is σ = 2544738351210. Its totient is φ = 656706671264.

The previous prime is 1313413342541. The next prime is 1313413342607. The reversal of 1313413342544 is 4452433143131.

It can be written as a sum of positive squares in only one way, i.e., 1242582842944 + 70830499600 = 1114712^2 + 266140^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1313413342498 and 1313413342507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313413342541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41044166939 + ... + 41044166970.

It is an arithmetic number, because the mean of its divisors is an integer number (254473835121).

Almost surely, 2^{1313413342544} is an apocalyptic number.

It is an amenable number.

1313413342544 is a deficient number, since it is larger than the sum of its proper divisors (1231325008666).

1313413342544 is an equidigital number, since it uses as much as digits as its factorization.

1313413342544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82088333917 (or 82088333911 counting only the distinct ones).

The product of its digits is 207360, while the sum is 38.

Adding to 1313413342544 its reverse (4452433143131), we get a palindrome (5765846485675).

The spelling of 1313413342544 in words is "one trillion, three hundred thirteen billion, four hundred thirteen million, three hundred forty-two thousand, five hundred forty-four".