1313420403423 has 4 divisors (see below), whose sum is σ = 1751227204568. Its totient is φ = 875613602280.

The previous prime is 1313420403397. The next prime is 1313420403457. The reversal of 1313420403423 is 3243040243131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-1313420403423 is a prime.

It is a super-2 number, since 2×1313420403423² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313420403623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218903400568 + ... + 218903400573.

It is an arithmetic number, because the mean of its divisors is an integer number (437806801142).

Almost surely, 2^{1313420403423} is an apocalyptic number.

1313420403423 is a deficient number, since it is larger than the sum of its proper divisors (437806801145).

1313420403423 is an equidigital number, since it uses as much as digits as its factorization.

1313420403423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437806801144.

The product of its (nonzero) digits is 20736, while the sum is 30.

Adding to 1313420403423 its reverse (3243040243131), we get a palindrome (4556460646554).

The spelling of 1313420403423 in words is "one trillion, three hundred thirteen billion, four hundred twenty million, four hundred three thousand, four hundred twenty-three".