131344023131240 has 64 divisors (see below), whose sum is σ = 312934608176400. Its totient is φ = 49442928427008.

The previous prime is 131344023131203. The next prime is 131344023131261. The reversal of 131344023131240 is 42131320443131.

131344023131240 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 8 ways, for example, as 125801661905956 + 5542361225284 = 11216134^2 + 2354222^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131344023131197 and 131344023131206.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 313649 + ... + 16210688.

Almost surely, 2^{131344023131240} is an apocalyptic number.

131344023131240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131344023131240 is an abundant number, since it is smaller than the sum of its proper divisors (181590585045160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131344023131240 is a wasteful number, since it uses less digits than its factorization.

131344023131240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16536054 (or 16536050 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131344023131240 its reverse (42131320443131), we get a palindrome (173475343574371).

The spelling of 131344023131240 in words is "one hundred thirty-one trillion, three hundred forty-four billion, twenty-three million, one hundred thirty-one thousand, two hundred forty".