131365411034000 has 480 divisors, whose sum is σ = 379724070791520. Its totient is φ = 43657996800000.

The previous prime is 131365411033981. The next prime is 131365411034003. The reversal of 131365411034000 is 430114563131.

It can be written as a sum of positive squares in 16 ways, for example, as 111864213721744 + 19501197312256 = 10576588^2 + 4416016^2 .

It is a super-2 number, since 2×131365411034000² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131365411034003) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 317539286 + ... + 317952714.

It is an arithmetic number, because the mean of its divisors is an integer number (791091814149).

Almost surely, 2^{131365411034000} is an apocalyptic number.

131365411034000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131365411034000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189862035395760).

131365411034000 is an abundant number, since it is smaller than the sum of its proper divisors (248358659757520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131365411034000 is a wasteful number, since it uses less digits than its factorization.

131365411034000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 413588 (or 413561 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 131365411034000 its reverse (430114563131), we get a palindrome (131795525597131).

The spelling of 131365411034000 in words is "one hundred thirty-one trillion, three hundred sixty-five billion, four hundred eleven million, thirty-four thousand".