131402321111141 has 2 divisors, whose sum is σ = 131402321111142. Its totient is φ = 131402321111140.

The previous prime is 131402321111123. The next prime is 131402321111143. The reversal of 131402321111141 is 141111123204131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131401996751041 + 324360100 = 11463071^2 + 18010^2 .

It is an emirp because it is prime and its reverse (141111123204131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131402321111141 - 2³⁴ = 131385141241957 is a prime.

Together with 131402321111143, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131402321111141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131402321111143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701160555570 + 65701160555571.

It is an arithmetic number, because the mean of its divisors is an integer number (65701160555571).

Almost surely, 2^{131402321111141} is an apocalyptic number.

It is an amenable number.

131402321111141 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402321111141 is an equidigital number, since it uses as much as digits as its factorization.

131402321111141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 26.

Adding to 131402321111141 its reverse (141111123204131), we get a palindrome (272513444315272).

The spelling of 131402321111141 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred twenty-one million, one hundred eleven thousand, one hundred forty-one".