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13140305444120 = 235328507636103
BaseRepresentation
bin1011111100110111011100…
…1111001111110100011000
31201112012102110221120120212
42333031313033033310120
53210242321143202440
643540323433110252
72524233006243341
oct277156717176430
951465373846525
1013140305444120
114206854946598
121582819858388
1374418290317a
14335dcc0430c8
1517bc220e0465
hexbf3773cfd18

13140305444120 has 16 divisors (see below), whose sum is σ = 29565687249360. Its totient is φ = 5256122177632.

The previous prime is 13140305444093. The next prime is 13140305444153. The reversal of 13140305444120 is 2144450304131.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164253818012 + ... + 164253818091.

It is an arithmetic number, because the mean of its divisors is an integer number (1847855453085).

Almost surely, 213140305444120 is an apocalyptic number.

13140305444120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13140305444120 is an abundant number, since it is smaller than the sum of its proper divisors (16425381805240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140305444120 is a wasteful number, since it uses less digits than its factorization.

13140305444120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 328507636114 (or 328507636110 counting only the distinct ones).

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 13140305444120 its reverse (2144450304131), we get a palindrome (15284755748251).

The spelling of 13140305444120 in words is "thirteen trillion, one hundred forty billion, three hundred five million, four hundred forty-four thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 328507636103 657015272206 1314030544412 1642538180515 2628061088824 3285076361030 6570152722060 13140305444120