13140311540112 has 60 divisors (see below), whose sum is σ = 36776996568000. Its totient is φ = 4379821005504.

The previous prime is 13140311540093. The next prime is 13140311540159. The reversal of 13140311540112 is 21104511304131.

13140311540112 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 3 + 1 + 1 + 540 + 112 = 666.

13140311540112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 702612 + ... + 5174387.

It is an arithmetic number, because the mean of its divisors is an integer number (612949942800).

Almost surely, 2^{13140311540112} is an apocalyptic number.

13140311540112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13140311540112 is an abundant number, since it is smaller than the sum of its proper divisors (23636685027888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140311540112 is a wasteful number, since it uses less digits than its factorization.

13140311540112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5892540 (or 5892531 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 13140311540112 its reverse (21104511304131), we get a palindrome (34244822844243).

The spelling of 13140311540112 in words is "thirteen trillion, one hundred forty billion, three hundred eleven million, five hundred forty thousand, one hundred twelve".