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1314034010543 = 1677868467129
BaseRepresentation
bin10011000111110010100…
…001111100100110101111
311122121202021211001111102
4103013302201330212233
5133012120201314133
62443354153113315
7163635662541122
oct23076241744657
94577667731442
101314034010543
11467307a40011
121928033b883b
1396bb37838a7
14478573963b9
15242ab0257e8
hex131f287c9af

1314034010543 has 4 divisors (see below), whose sum is σ = 1321902477840. Its totient is φ = 1306165543248.

The previous prime is 1314034010521. The next prime is 1314034010557. The reversal of 1314034010543 is 3450104304131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314034010543 - 236 = 1245314533807 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314034010593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3934233398 + ... + 3934233731.

It is an arithmetic number, because the mean of its divisors is an integer number (330475619460).

Almost surely, 21314034010543 is an apocalyptic number.

1314034010543 is a deficient number, since it is larger than the sum of its proper divisors (7868467297).

1314034010543 is an equidigital number, since it uses as much as digits as its factorization.

1314034010543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7868467296.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1314034010543 its reverse (3450104304131), we get a palindrome (4764138314674).

The spelling of 1314034010543 in words is "one trillion, three hundred fourteen billion, thirty-four million, ten thousand, five hundred forty-three".

Divisors: 1 167 7868467129 1314034010543