131404013120 has 56 divisors (see below), whose sum is σ = 313313292600. Its totient is φ = 52493156352.

The previous prime is 131404013119. The next prime is 131404013141. The reversal of 131404013120 is 21310404131.

It can be written as a sum of positive squares in 4 ways, for example, as 43674312256 + 87729700864 = 208984^2 + 296192^2 .

It is a super-2 number, since 2×131404013120² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 131404013092 and 131404013101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20915 + ... + 513074.

It is an arithmetic number, because the mean of its divisors is an integer number (5594880225).

Almost surely, 2^131404013120 is an apocalyptic number.

131404013120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131404013120 is an abundant number, since it is smaller than the sum of its proper divisors (181909279480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131404013120 is an equidigital number, since it uses as much as digits as its factorization.

131404013120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 534775 (or 534765 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131404013120 its reverse (21310404131), we get a palindrome (152714417251).

The spelling of 131404013120 in words is "one hundred thirty-one billion, four hundred four million, thirteen thousand, one hundred twenty".