13140404401240 has 64 divisors (see below), whose sum is σ = 29755563868800. Its totient is φ = 5222448511488.

The previous prime is 13140404401237. The next prime is 13140404401259. The reversal of 13140404401240 is 4210440404131.

It is a junction number, because it is equal to n+sod(n) for n = 13140404401199 and 13140404401208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 227790721 + ... + 227848399.

It is an arithmetic number, because the mean of its divisors is an integer number (464930685450).

Almost surely, 2^{13140404401240} is an apocalyptic number.

13140404401240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13140404401240 is an abundant number, since it is smaller than the sum of its proper divisors (16615159467560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140404401240 is a wasteful number, since it uses less digits than its factorization.

13140404401240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94124 (or 94120 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 13140404401240 its reverse (4210440404131), we get a palindrome (17350844805371).

The spelling of 13140404401240 in words is "thirteen trillion, one hundred forty billion, four hundred four million, four hundred one thousand, two hundred forty".