13141234544045 has 8 divisors (see below), whose sum is σ = 15772757916696. Its totient is φ = 10510803326016.

The previous prime is 13141234544027. The next prime is 13141234544063. The reversal of 13141234544045 is 54044543214131.

It is an interprime number because it is at equal distance from previous prime (13141234544027) and next prime (13141234544063).

It can be written as a sum of positive squares in 4 ways, for example, as 133360814596 + 13007873729449 = 365186^2 + 3606643^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13141234544045 - 2²⁰ = 13141233495469 is a prime.

It is a super-3 number, since 3×13141234544045³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13141234543993 and 13141234544011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 273012182 + ... + 273060311.

It is an arithmetic number, because the mean of its divisors is an integer number (1971594739587).

Almost surely, 2^{13141234544045} is an apocalyptic number.

It is an amenable number.

13141234544045 is a deficient number, since it is larger than the sum of its proper divisors (2631523372651).

13141234544045 is an equidigital number, since it uses as much as digits as its factorization.

13141234544045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 546077311.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 13141234544045 its reverse (54044543214131), we get a palindrome (67185777758176).

The spelling of 13141234544045 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty-four million, five hundred forty-four thousand, forty-five".