Base | Representation |
---|---|
bin | 1011111100111010111010… |
… | …0111011110110110110010 |
3 | 1201112021211020012202002101 |
4 | 2333032232213132312302 |
5 | 3210301222020402200 |
6 | 43540555543011014 |
7 | 2524265020411444 |
oct | 277165647366662 |
9 | 51467736182071 |
10 | 13141234544050 |
11 | 4207191344078 |
12 | 1582a38a39a6a |
13 | 7442a0247c42 |
14 | 3360795b6494 |
15 | 17bc7896926a |
hex | bf3ae9dedb2 |
13141234544050 has 48 divisors (see below), whose sum is σ = 24473136654720. Its totient is φ = 5249950395840.
The previous prime is 13141234544027. The next prime is 13141234544063. The reversal of 13141234544050 is 5044543214131.
It is a happy number.
It is a super-2 number, since 2×131412345440502 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 193895469 + ... + 193963231.
It is an arithmetic number, because the mean of its divisors is an integer number (509857013640).
Almost surely, 213141234544050 is an apocalyptic number.
13141234544050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13141234544050 is a deficient number, since it is larger than the sum of its proper divisors (11331902110670).
13141234544050 is a wasteful number, since it uses less digits than its factorization.
13141234544050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72547 (or 72542 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 13141234544050 its reverse (5044543214131), we get a palindrome (18185777758181).
The spelling of 13141234544050 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty-four million, five hundred forty-four thousand, fifty".
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