131413140142301 has 4 divisors (see below), whose sum is σ = 139143324856572. Its totient is φ = 123682955428032.

The previous prime is 131413140142283. The next prime is 131413140142351. The reversal of 131413140142301 is 103241041314131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 113966855376676 + 17446284765625 = 10675526^2 + 4176875^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131413140142301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131413140142351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3865092357110 + ... + 3865092357143.

It is an arithmetic number, because the mean of its divisors is an integer number (34785831214143).

Almost surely, 2^{131413140142301} is an apocalyptic number.

It is an amenable number.

131413140142301 is a deficient number, since it is larger than the sum of its proper divisors (7730184714271).

131413140142301 is an equidigital number, since it uses as much as digits as its factorization.

131413140142301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7730184714270.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 131413140142301 its reverse (103241041314131), we get a palindrome (234654181456432).

The spelling of 131413140142301 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred forty million, one hundred forty-two thousand, three hundred one".