Base | Representation |
---|---|
bin | 10011000111111101110… |
… | …001000001011111110011 |
3 | 11122122020102111221001010 |
4 | 103013331301001133303 |
5 | 133013011430341430 |
6 | 2443425005242003 |
7 | 163643442015312 |
oct | 23077561013763 |
9 | 4578212457033 |
10 | 1314222512115 |
11 | 4673a438a037 |
12 | 192856563303 |
13 | 96c13843296 |
14 | 47874424279 |
15 | 242bc85ccb0 |
hex | 131fdc417f3 |
1314222512115 has 64 divisors (see below), whose sum is σ = 2244448604160. Its totient is φ = 654375905280.
The previous prime is 1314222512101. The next prime is 1314222512153. The reversal of 1314222512115 is 5112152224131.
It is not a de Polignac number, because 1314222512115 - 218 = 1314222249971 is a prime.
It is a super-2 number, since 2×13142225121152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15783522 + ... + 15866568.
It is an arithmetic number, because the mean of its divisors is an integer number (35069509440).
Almost surely, 21314222512115 is an apocalyptic number.
1314222512115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1314222512115 is a deficient number, since it is larger than the sum of its proper divisors (930226092045).
1314222512115 is a wasteful number, since it uses less digits than its factorization.
1314222512115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83572.
The product of its digits is 4800, while the sum is 30.
Adding to 1314222512115 its reverse (5112152224131), we get a palindrome (6426374736246).
The spelling of 1314222512115 in words is "one trillion, three hundred fourteen billion, two hundred twenty-two million, five hundred twelve thousand, one hundred fifteen".
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