Base | Representation |
---|---|
bin | 1011111100111110101100… |
… | …1010011100101111111100 |
3 | 1201112101110000121200212021 |
4 | 2333033223022130233330 |
5 | 3210310312041442140 |
6 | 43541244431045524 |
7 | 2524332133514602 |
oct | 277175312345774 |
9 | 51471400550767 |
10 | 13142250343420 |
11 | 4207662779190 |
12 | 15830810708a4 |
13 | 744402827563 |
14 | 336134477872 |
15 | 17bcd7c1bb4a |
hex | bf3eb29cbfc |
13142250343420 has 48 divisors (see below), whose sum is σ = 30275900323200. Its totient is φ = 4752301785920.
The previous prime is 13142250343393. The next prime is 13142250343441. The reversal of 13142250343420 is 2434305224131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 166825150 + ... + 166903909.
It is an arithmetic number, because the mean of its divisors is an integer number (630747923400).
Almost surely, 213142250343420 is an apocalyptic number.
13142250343420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142250343420 is an abundant number, since it is smaller than the sum of its proper divisors (17133649979780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142250343420 is a wasteful number, since it uses less digits than its factorization.
13142250343420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 333729258 (or 333729256 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 13142250343420 its reverse (2434305224131), we get a palindrome (15576555567551).
The spelling of 13142250343420 in words is "thirteen trillion, one hundred forty-two billion, two hundred fifty million, three hundred forty-three thousand, four hundred twenty".
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