Base | Representation |
---|---|
bin | 10011000111111111011… |
… | …011001111001010010000 |
3 | 11122122022100220111202211 |
4 | 103013333123033022100 |
5 | 133013041042332334 |
6 | 2443431442121504 |
7 | 163644230462023 |
oct | 23077733171220 |
9 | 4578270814684 |
10 | 1314250355344 |
11 | 467409077073 |
12 | 192863950294 |
13 | 96c19541674 |
14 | 47877dd11ba |
15 | 242c000ca64 |
hex | 131ff6cf290 |
1314250355344 has 20 divisors (see below), whose sum is σ = 2696145950124. Its totient is φ = 618470755328.
The previous prime is 1314250355323. The next prime is 1314250355371. The reversal of 1314250355344 is 4435530524131.
It can be written as a sum of positive squares in 2 ways, for example, as 503191609600 + 811058745744 = 709360^2 + 900588^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1314250355297 and 1314250355306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2415901117 + ... + 2415901660.
Almost surely, 21314250355344 is an apocalyptic number.
It is an amenable number.
1314250355344 is an abundant number, since it is smaller than the sum of its proper divisors (1381895594780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314250355344 is a wasteful number, since it uses less digits than its factorization.
1314250355344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4831802802 (or 4831802796 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 1314250355344 its reverse (4435530524131), we get a palindrome (5749780879475).
The spelling of 1314250355344 in words is "one trillion, three hundred fourteen billion, two hundred fifty million, three hundred fifty-five thousand, three hundred forty-four".
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