Base | Representation |
---|---|
bin | 11101111000011111011001… |
… | …010111000111010100111100 |
3 | 122020100010210200101121002022 |
4 | 131320133121113013110330 |
5 | 114211233104324134000 |
6 | 1143303550040415312 |
7 | 36453111500305526 |
oct | 3570373127072474 |
9 | 566303720347068 |
10 | 131425351005500 |
11 | 389701a6433132 |
12 | 128a7144177538 |
13 | 5844485341316 |
14 | 2465041600a16 |
15 | 102da1d112585 |
hex | 7787d95c753c |
131425351005500 has 48 divisors (see below), whose sum is σ = 287041328150304. Its totient is φ = 52568608982400.
The previous prime is 131425351005463. The next prime is 131425351005517. The reversal of 131425351005500 is 5500153524131.
It is a super-2 number, since 2×1314253510055002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13430192 + ... + 21052808.
It is an arithmetic number, because the mean of its divisors is an integer number (5980027669798).
Almost surely, 2131425351005500 is an apocalyptic number.
131425351005500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131425351005500 is an abundant number, since it is smaller than the sum of its proper divisors (155615977144804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131425351005500 is a wasteful number, since it uses less digits than its factorization.
131425351005500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7657119 (or 7657107 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 131425351005500 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, three hundred fifty-one million, five thousand, five hundred".
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