13143311403102 has 80 divisors (see below), whose sum is σ = 30779019976320. Its totient is φ = 4184102968848.

The previous prime is 13143311403083. The next prime is 13143311403121. The reversal of 13143311403102 is 20130411334131.

13143311403102 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 331 + 14 + 0 + 310 + 2 = 666.

It is an interprime number because it is at equal distance from previous prime (13143311403083) and next prime (13143311403121).

It is a super-2 number, since 2×13143311403102² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 347152 + ... + 5138787.

It is an arithmetic number, because the mean of its divisors is an integer number (384737749704).

Almost surely, 2^{13143311403102} is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13143311403102, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15389509988160).

13143311403102 is an abundant number, since it is smaller than the sum of its proper divisors (17635708573218).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13143311403102 is a wasteful number, since it uses less digits than its factorization.

13143311403102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5486619 (or 5486610 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 13143311403102 its reverse (20130411334131), we get a palindrome (33273722737233).

The spelling of 13143311403102 in words is "thirteen trillion, one hundred forty-three billion, three hundred eleven million, four hundred three thousand, one hundred two".