Base | Representation |
---|---|
bin | 111101001101000001… |
… | …0111001001000100101 |
3 | 110120020211020222200000 |
4 | 1322122002321020211 |
5 | 4123133431442303 |
6 | 140214003211513 |
7 | 12332021022450 |
oct | 1723202711045 |
9 | 416224228600 |
10 | 131433468453 |
11 | 50816848201 |
12 | 21580976b99 |
13 | c517b70c11 |
14 | 650ba10497 |
15 | 3643b19da3 |
hex | 1e9a0b9225 |
131433468453 has 96 divisors (see below), whose sum is σ = 228808280064. Its totient is φ = 73839978432.
The previous prime is 131433468451. The next prime is 131433468461. The reversal of 131433468453 is 354864334131.
131433468453 is a `hidden beast` number, since 1 + 3 + 143 + 3 + 468 + 45 + 3 = 666.
It is not a de Polignac number, because 131433468453 - 21 = 131433468451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131433468399 and 131433468408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131433468451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 90830976 + ... + 90832422.
It is an arithmetic number, because the mean of its divisors is an integer number (2383419584).
Almost surely, 2131433468453 is an apocalyptic number.
It is an amenable number.
131433468453 is a deficient number, since it is larger than the sum of its proper divisors (97374811611).
131433468453 is an equidigital number, since it uses as much as digits as its factorization.
131433468453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2333 (or 2321 counting only the distinct ones).
The product of its digits is 1244160, while the sum is 45.
The spelling of 131433468453 in words is "one hundred thirty-one billion, four hundred thirty-three million, four hundred sixty-eight thousand, four hundred fifty-three".
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